Windows Credentials Prevents Adding of Printer

If you ever encounter a problem where one computer (Let's call it computer A) cannot see the printer hooked up to another computer (Let's call it computer B) in your wireless home network, you might want to check if Computer A has existing windows credentials associated with Computer B. The credentials basically allow Computer A to log on to Computer B. So if the credentials have a wrong username or password, say a blank password, then Computer B will prevent Computer A from logging on and using any resources attached to it (In this case, the printer attached to computer B). Check out and study up on Windows Credentials Manager.

So to solve the problem, all I had to do was delete any existing credentials associated with Computer B that were stored on Computer A. Then, I tried adding the printer once more, this time, making sure I had the right username and password for logging on to Computer B. Afterwards, the printer could now be seen by Computer A. Printed out a test page to ensure that everything was working properly.

Area of any n equal-sided polygon

I remember deriving this formula in high school.
Let:
n = number of sides
s = length of a side

Area of Polygon = (n(s^2))/(4tan(180/n))

To check quickly, for a square,
n = 4
tan(45) = 1

Area of a square = (4(s^2))/(4(1)) = s^2

It is interesting to note that the Area of a Polygon approximates the Area of a Circle when n approaches a very large value, say infinity. But as n approaches a very large value, the value of s approaches zero since the length of a side almost becomes a point. We have to modify our Area of a Polygon formula so that we represent the length of a side with the polygon's apothem. (And as n approaches infinity, this is also the radius of a circle).

a = apothem length = radius of a circle
s = a(2(tan(180/n))

Area of Polygon = n(a^2)(tan(180/n)

In this formula, as n approaches infinity, then the formula approximates the area of a circle.

Area of a Circle = π(a^2)

So, π can be approximated.

π = n(tan(180/n))

You can try out any number which is relatively larger than 180, say 100,000 and compute for the value of π. When n =100,000, π = 3.14159.

It is also interesting for me that (π/n) = tan (180/n). From trigonometry, we know that tan(Θ) = Opposite/Adjacent. tan(180/n) = π/n. So we have a right triangle with π for the opposite side and n for the adjacent side. The term (180/n) is actually (360/2n). We are dividing 360 degrees by twice the value of n. As n approaches infinity, the angle approaches zero and we get the value of π.

Realme C2 Product Review

Purchased a Realme C2 Android Phone today for 4,990 pesos. It only comes with a charger and charging cable, unlike other smart phones I've bought before which include earphones and a protective case. I even had to shell out an extra 250 pesos for a protective case. Specs are as follows:

• Model RMX1941
• ColorOS Version V6.0
• Android Version 9
• Processor Octa Core
• RAM 2.0 GB
• Device Storage 16.0 GB
• Front Camera 5 Megapixels
• Rear Camera 13 Megapixels

According to the seller, the Realme brand is a sub-brand of OPPO. The device has a 1-year warranty so if I need to have it fixed, I just have to bring it to an OPPO service center.

I am excited to explore how this device will perform compared to my last phone, an SKK Hyper X Core. Too bad, the SKK brand is no longer available. Hope the Realme brand lasts longer since it is connected with OPPO.

The only concern that the sales person told me about was that this product likes to do automatic updates frequently. And true enough, as soon as I connected with our home wifi network, it already wanted to download the latest Android OS update. I appreciate that apps like Chrome and a File Manager are already installed. Had to add Grab, Viber, etc. and these installed seamlessly, too.

The screen is a bit longer than my last phone. Specs wise, I think that the only difference is that this phone has an Octa Core processor and Android 9 for the OS.

I'm still trying to get used to the (X) button for closing apps. I'm not really sure if it closes all the apps that are open, or closes all but the one on the screen when you press it. But other than this small annoyance, I think that the phone is performing well.

Will try to update this article if I find more things I like or dislike about the phone.